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关注：1
2013-05-23 12:21
求翻译：(4) Since operator ‘*’ on the top of the operator stack has higher priority than its previous one ‘+’ and higher than the current one ‘—’, current value 3’ is used to execute multiplication with ‘2’ popped up from the value stack. The result is pushed back into the value stack, while current operator ‘—’ is pushed into是什么意思？ 待解决
 悬赏分：1
- 离问题结束还有
(4) Since operator ‘*’ on the top of the operator stack has higher priority than its previous one ‘+’ and higher than the current one ‘—’, current value 3’ is used to execute multiplication with ‘2’ popped up from the value stack. The result is pushed back into the value stack, while current operator ‘—’ is pushed into
问题补充： |
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2013-05-23 12:21:38
正在翻译，请等待...
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2013-05-23 12:23:18
(4)，因为操作员“*”在操作员堆的上面比它早先一个有特别优先权“+”和高于当前一个“—”，当前值3'用于执行与“2\"的增殖突然出现从价值堆。结果被推回入价值堆，而当前操作员“—”被推挤入操作员堆。
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2013-05-23 12:24:58
(4) ，因为操作员`*’在操作员堆的上面比它的早先一`当前一`有重要性+’和更加高于-’，当前值3’用于执行增殖与从价值堆2’突然出现的`。 结果被推回入价值堆，而当前操作员`-’被推挤入操作员堆。
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2013-05-23 12:26:38
(4) 自运算符 '*' 上该运算符堆栈有更高的优先级比其前一个 '+' 和高于当前' — — '，3' 的当前值用于执行乘法与 2' 从堆栈中弹出值。结果值堆栈中，而当前运营商推回到 ' — —' 推入运算符堆栈。
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2013-05-23 12:28:18
[4]由于操作员'*'的顶部上的堆栈的操作符的优先级高于其上一个一个'+',高于当前一个'-','当前值3是用于执行乘法与'2'弹出堆栈的值。 结果是被推回到值栈,而当前运算符“-”推入操作堆栈中。
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