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关注：1
2013-05-23 12:21
求翻译：Compound 4 showed an almost identical set of spectra as compound 2, except that C-9′ was a methyl ester. For this reason, compound 4 was identified as the methyl ester of 2, and correspondingly named yunnaneic acid J. Compound 5, on the basis of its NMR spectra, was identified as the C-9 free acid form of compound 1 an是什么意思？ 待解决
 悬赏分：1
- 离问题结束还有
Compound 4 showed an almost identical set of spectra as compound 2, except that C-9′ was a methyl ester. For this reason, compound 4 was identified as the methyl ester of 2, and correspondingly named yunnaneic acid J. Compound 5, on the basis of its NMR spectra, was identified as the C-9 free acid form of compound 1 an
问题补充： |
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2013-05-23 12:21:38
正在翻译，请等待...
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2013-05-23 12:23:18
化合物4显示了几乎相同套光谱作为化合物2，除了C-9 ′是甲基酯。为此，化合物4被辨认了作为甲基酯2和根据它的核磁共振光相应地说出yunnaneic酸J. Compound 5名字，任意被辨认了作为化合物1的C-9酸形式和因而命名了rufescenolide D。化合物核磁共振的数据2-5显示
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2013-05-23 12:24:58
化合物4显示了几乎相同套光谱作为化合物2，除了C-9 ′是甲基酯。 为此，化合物4被辨认了作为甲基酯2和相应地命名了yunnaneic酸J。 化合物5，根据它的核磁共振光，任意被辨认了作为化合物1的C-9酸形式和因而命名了rufescenolide D。 化合物核磁共振的数据2-5显示
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2013-05-23 12:26:38
正在翻译，请等待...
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2013-05-23 12:28:18
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