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关注：1
2013-05-23 12:21
求翻译：As long as 2v + Δ > M, at least one message will be waiting in the server queue for the next request. If 2v + Δ < M, polling should be able to keep up with the real-time measurements. In the worst case, the server receives the poll request immediately before the sensor takes a measurement, and the polling observed late是什么意思？ 待解决
 悬赏分：1
- 离问题结束还有
As long as 2v + Δ > M, at least one message will be waiting in the server queue for the next request. If 2v + Δ < M, polling should be able to keep up with the real-time measurements. In the worst case, the server receives the poll request immediately before the sensor takes a measurement, and the polling observed late
问题补充： |
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2013-05-23 12:21:38
只要2V +Δ >男，至少一个消息将等待在服务员队列为下一个请求。
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2013-05-23 12:23:18
正在翻译，请等待...
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2013-05-23 12:24:58
只要2v + Δ > M，至少一则消息在服务器队列等待下个请求。 If 2v + Δ < M, polling should be able to keep up with the real-time measurements. 在最坏，服务器收到民意测验请求，在传感器采取测量之前，并且投票观察潜在因素是3v + Δ。 In the best case， a poll request arrives immediately after the sensor takes a measurement， and the observed latency is v. 假设，民意测验请求在一
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2013-05-23 12:26:38
正在翻译，请等待...
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2013-05-23 12:28:18
正在翻译，请等待...
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