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关注:1
2013-05-23 12:21
求翻译:Pipet 2.5 mL of the standard solution, and add the mobile phase to make exactly 50mL. Confirm that the peak area of bepotastine obtained with 20 mL of this solution is equivalent to 3.5 to 6.5z of that obtained with 20 mL of the standard solution.是什么意思?![]() ![]() Pipet 2.5 mL of the standard solution, and add the mobile phase to make exactly 50mL. Confirm that the peak area of bepotastine obtained with 20 mL of this solution is equivalent to 3.5 to 6.5z of that obtained with 20 mL of the standard solution.
问题补充: |
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2013-05-23 12:21:38
吸取2.5毫升标准溶液,并加入流动相,使恰好50毫升。
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2013-05-23 12:23:18
pipet2.5ml的标准的解决方案,并将其添加到移动阶段精确50ml。 确认bepotastine山顶区获得的20毫升此解决方案相当于3.5至6.5Z的,所取得的20ml的标准的解决方案。
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2013-05-23 12:24:58
吸取标准解法的2.5机器语言,并且增加流动相确切地做50mL。 证实bepotastine高峰地区得到以20机器语言这种解答是相当于3.5与那的6.5z获得以标准解法的20机器语言。
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2013-05-23 12:26:38
吸管 2.5 毫升的标准溶液,加流动相使完全 50 毫升。确认的贝托斯汀获得 20 毫升的这种解决方案与峰面积等于 3.5 到 6.5z 的获得与标准溶液 20ml。
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2013-05-23 12:28:18
正在翻译,请等待...
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