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关注：1
2013-05-23 12:21
求翻译：The residual, {37938}r{37939}n{37940}{37941}, is the difference between the right hand side of the system of equations, {37942}b{37943}, and the coefficient matrix, {37944}A{37945}, multiplied by the approximate solution at the {37946}n{37947}{37948}th{37949} iteration, {37950}x{37951}n{37952}{37953}: {37954}r{37955}n{是什么意思？ 待解决
 悬赏分：1
- 离问题结束还有
The residual, {37938}r{37939}n{37940}{37941}, is the difference between the right hand side of the system of equations, {37942}b{37943}, and the coefficient matrix, {37944}A{37945}, multiplied by the approximate solution at the {37946}n{37947}{37948}th{37949} iteration, {37950}x{37951}n{37952}{37953}: {37954}r{37955}n{
问题补充： |
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2013-05-23 12:21:38
正在翻译，请等待...
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2013-05-23 12:23:18
剩余{37938}R{37939}{37940}{37941},之间的区别是系统的右边的方程式,{37942}B{37943},系数矩阵,{37944}{37945},乘以大致的解决方案{37946}n{37947}{37948}{37949}次迭代,{37950}x{37951}{37952}{37953}{37954}R{37955}{37956}=B-ax{37957}{37958}{37959}。
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2013-05-23 12:24:58
残余， (37938) r( 37939) n( 37940)( 37941)，是在方程组的右边， 37942 b (37943)(和)系数矩阵， 37944 A (37945之间的)(区别)，乘以近似解答在 (37946) n( 37947)( 37948) th( 37949) 叠代， (37950) x( 37951) n( 37952)( 37953) ： (37954) r( 37955) n( 37956) = b -轴(37957) n( 37958)( 37959)。
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2013-05-23 12:26:38
残余，{37938} r {37939} n {37940} {37941}，右手边的方程组，{37942} b 之间的区别是 {37943}，和系数矩阵，{37944} {37945}，乘以 {37946} n {37947} {37948} th {37949} 迭代，{37950} 的近似解 x {37951} n {37952} {37953}: r {37954} {37955} n {37956} = b-Ax {37957} n {37958} {37959}。
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2013-05-23 12:28:18
正在翻译，请等待...
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