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  • 匿名
关注:1 2013-05-23 12:21

求翻译:8次移位运行后(每当溢出位变成1时,必须如第4步所述进行异或运行),用前一次运行的结果和下一次的数据包(8位功能码)进行异或运行。这次运行的结果必须再次移位8次,当移位中溢出位是1时,需要与固定值A001H进行异或。是什么意思?

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8次移位运行后(每当溢出位变成1时,必须如第4步所述进行异或运行),用前一次运行的结果和下一次的数据包(8位功能码)进行异或运行。这次运行的结果必须再次移位8次,当移位中溢出位是1时,需要与固定值A001H进行异或。
问题补充:

  • 匿名
2013-05-23 12:21:38
8 shift run (whenever the overflow bit to become 1 must be such as described in Step 4, the XOR operation) with the first run results and the next packet (8-bit function code) XOR operation. The results of this run must shift 8 times again, when the shift in the overflow bit is 1, with a fixed value
  • 匿名
2013-05-23 12:23:18
Place 8 times after running (when overflow bits becomes 1, it must, as described in step 4 for exclusive-OR operation), the previous run of results and the next packet (8-Bit function code) for exclusive-OR operation. This time the results must be run again to shift 8 times, when you shift out of th
  • 匿名
2013-05-23 12:24:58
(When after 8 shifting movements overflow shift becomes 1, must like 4th step institute state carries on different or movement), with the result and the next time data packet which preceding time moves (8 functional codes) carry on different or the movement.This movement result must shift once more
  • 匿名
2013-05-23 12:26:38
After shift runs 8 (whenever the overflow bit becomes 1 o'clock must be as described in the 4th step is exclusive-or operation), with the results of the first run and the next packet (8-bit function code) for exclusive-or operation. This run of results must once again shift 8 times when overflow bit
  • 匿名
2013-05-23 12:28:18
正在翻译,请等待...
 
 
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