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关注：1
2013-05-23 12:21
求翻译：假设中间轮等速转动且不考虑摩擦损失，则中间轮的单个轮齿受到的最大圆周力为262.5N，故法向啮合力为279N。是什么意思？ 待解决
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- 离问题结束还有
假设中间轮等速转动且不考虑摩擦损失，则中间轮的单个轮齿受到的最大圆周力为262.5N，故法向啮合力为279N。
问题补充： |
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2013-05-23 12:21:38
Assuming constant rotation round the middle and does not consider friction losses, the middle rounds of the maximum circumference of a single tooth by force 262.5N, so the normal meshing force 279N.
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2013-05-23 12:23:18
Assuming such as intermediate round spinning as soon as possible, and not taking into account friction loss among the single pulley wheel circumference by far the greatest power, the law for 262.5 N arcuate to 279 N for power.
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2013-05-23 12:24:58
The supposition loose roller constant speed rotation also did not consider the friction loses, then the loose roller single gear teeth receive the biggest twisting couple######### twisting force is 262.5N, therefore the normal engaging force is 279N.
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2013-05-23 12:26:38
Assuming speed wheel rotation and does not take into account friction losses in the Middle, the Middle for the maximum circumference of the wheel of a single tooth were force 262.5N, thus making the normal meshing force to 279N.
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2013-05-23 12:28:18
Assuming constant rotation round the middle and does not consider friction losses, the middle rounds of the maximum circumference of a single tooth by force 262.5N, so the normal meshing force 279N.
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