求翻译：所建模型的厚度与其长度和宽度相比很小，所以计算是基于有限厚度无限大平壁进行的。取图1所示模型的中纵截面，如图2所示，在t=0时刻，通入电流密度为J0的电流时，将在裂纹尖端(x0,y0,0)产生一功率密度为q的点热源，则在试件中某一点（x,y,z）在t时刻温度升高为：是什么意思？

Built compared to the model the thickness of its length and width is very small, so the calculation is based on the finite thickness infinite Ohira wall. Take the model shown in Figure 1 in longitudinal section, as shown in Figure 2, at time t = 0, which leads to current density j0 current will prod

Building a model of the thickness when compared with its length and width is very small, so limited thickness is calculated based on the infinity level the wall. The model shown in Figure 1 in the longitudinal section, as shown in Figure 2, time t = 0, the current density is J 0 of the current, the

If modelling thickness the length and the width compare very slightly, therefore the computation is carries on based on the limited thickness infinitely great even wall.Takes shown in Figure 1 the model the longitudinal cross section, as shown in Figure 2, when the t=0 time, passes over the current

Model thickness compared to its length and width is very small, so it is based on finite thickness an infinite wall. Longitudinal cross section in the preparation of model shown in Figure 1, as shown in Figure 2, in t=0 times, into the current of current density is J0, crack-tip (x0,y0,0) produces a

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