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关注：1
2013-05-23 12:21
求翻译：From a mechanistic point of view, the relaxation mechanism involves ESIPT from the S1 state occurring in the femtosecond timescale [4,5], then radiative decay of the excited keto tautomer (fluorescence emission with a large Stokes shift) is followed by back proton transfer, causing a return to the ground state phenol (是什么意思？ 待解决
 悬赏分：1
- 离问题结束还有
From a mechanistic point of view, the relaxation mechanism involves ESIPT from the S1 state occurring in the femtosecond timescale [4,5], then radiative decay of the excited keto tautomer (fluorescence emission with a large Stokes shift) is followed by back proton transfer, causing a return to the ground state phenol (
问题补充： |
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2013-05-23 12:21:38
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2013-05-23 12:23:18
从机械的角度看,放松机制涉及ESIPT从S 1状态中发生的时间标尺femtosecond[4.5],然后辐射衰减的激动的凯托(tautomer萤光的排放有大孖士打律师行shift)后面回质子转移,导致返回地面状态的酚类化合物(或)enol form(方案1)
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2013-05-23 12:24:58
从一个机构观点，放松机制在飞秒时标4,5介入ESIPT从S1状态 (发生)，然后激动的keto tautomer荧光放射的 (辐射衰变与大升火转移) 由后面质子传递跟随，导致回归到地面情况酚 (或enol) 形式 (计划1)
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2013-05-23 12:26:38
从机械的角度来看，弛豫机制涉及从 S1 状态发生 [4，5]，飞秒时间刻度中 ESIPT 然后辐射衰变的兴奋的酮互变异构体 (荧光发射与大的斯托克斯位移) 是由反质子转移，导致回到基态苯酚 (或烯醇) 形式 (方案 1)
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2013-05-23 12:28:18
正在翻译，请等待...
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